Basic Trigonometric Ratios

sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
csc θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ

Introduction to Trigonometric Identities

Trigonometric identities are equations involving trigonometric functions that are true for all values of the variables for which both sides of the equation are defined. These identities are essential tools in mathematics, physics, engineering, and many other fields.

Why Trigonometric Identities Matter:

  • Simplify complex trigonometric expressions
  • Solve trigonometric equations
  • Prove mathematical statements
  • Model periodic phenomena in science and engineering
  • Essential for calculus, physics, and signal processing

This comprehensive guide covers all major trigonometric identities with detailed explanations, proofs, and practical examples to help you master this essential mathematical topic.

Basic Trigonometric Identities

These are the fundamental identities that form the foundation of all trigonometric relationships:

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Reciprocal Identities

csc θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ

These identities define the reciprocal relationships between the six trigonometric functions.

Quotient Identities

tan θ = sin θ/cos θ
cot θ = cos θ/sin θ

These show how tangent and cotangent relate to sine and cosine.

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Co-function Identities

sin(π/2 - θ) = cos θ
cos(π/2 - θ) = sin θ
tan(π/2 - θ) = cot θ

These relate trigonometric functions of complementary angles.

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Even-Odd Identities

sin(-θ) = -sin θ (odd)
cos(-θ) = cos θ (even)
tan(-θ) = -tan θ (odd)

These describe the symmetry properties of trigonometric functions.

Proof of Quotient Identity tan θ = sin θ/cos θ:

Starting from the definitions in a right triangle:

tan θ = opposite/adjacent

sin θ = opposite/hypotenuse

cos θ = adjacent/hypotenuse

Therefore: sin θ/cos θ = (opposite/hypotenuse) ÷ (adjacent/hypotenuse) = opposite/adjacent = tan θ

Track your progress by practicing with the trigonometry calculator.

Pythagorean Identities

These identities are derived from the Pythagorean Theorem and are among the most important trigonometric identities:

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Fundamental Identity

sin²θ + cos²θ = 1

The most basic Pythagorean identity, true for all angles θ.

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Tangent-Secant Identity

1 + tan²θ = sec²θ

Derived by dividing the fundamental identity by cos²θ.

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Cotangent-Cosecant Identity

1 + cot²θ = csc²θ

Derived by dividing the fundamental identity by sin²θ.

Proof of sin²θ + cos²θ = 1:

Consider a right triangle with hypotenuse = 1 (unit circle approach):

In a unit circle, any point on the circle has coordinates (cos θ, sin θ)

The distance from the origin is: √[(cos θ)² + (sin θ)²] = 1

Squaring both sides: cos²θ + sin²θ = 1

This identity holds for all real values of θ.

Example: If sin θ = 3/5, find cos θ using Pythagorean identity.

Solution:

sin²θ + cos²θ = 1

(3/5)² + cos²θ = 1

9/25 + cos²θ = 1

cos²θ = 1 - 9/25 = 16/25

cos θ = ±4/5 (sign depends on quadrant)

Sum and Difference Formulas

These formulas express trigonometric functions of sums or differences of angles in terms of functions of the individual angles:

Sine Sum/Difference

sin(A ± B) = sin A cos B ± cos A sin B

Note: Use + for sum, - for difference on the right side.

Cosine Sum/Difference

cos(A ± B) = cos A cos B ∓ sin A sin B

Note: Use - for sum, + for difference on the right side.

Tangent Sum/Difference

tan(A ± B) = (tan A ± tan B)/(1 ∓ tan A tan B)

Upper signs correspond, lower signs are opposite.

Proof of cos(A - B) = cos A cos B + sin A sin B:

Consider two points on the unit circle:

Point P at angle A: (cos A, sin A)

Point Q at angle B: (cos B, sin B)

Distance PQ² = (cos A - cos B)² + (sin A - sin B)²

Using law of cosines in triangle OPQ: PQ² = 1² + 1² - 2(1)(1)cos(A - B)

Equate both expressions and simplify to get the formula.

Example: Find the exact value of sin(75°).

Solution:

sin(75°) = sin(45° + 30°) = sin45°cos30° + cos45°sin30°

= (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4

Strengthen your understanding by practicing real examples with the trigonometry calculator.

Double Angle Formulas

These formulas express trigonometric functions of 2θ in terms of functions of θ:

Sine Double Angle

sin 2θ = 2 sin θ cos θ

Derived from sin(θ + θ) using sum formula.

Cosine Double Angle

cos 2θ = cos²θ - sin²θ
= 2 cos²θ - 1
= 1 - 2 sin²θ

Three equivalent forms using Pythagorean identity.

Tangent Double Angle

tan 2θ = 2 tan θ/(1 - tan²θ)

Valid when tan θ ≠ ±1 and cos 2θ ≠ 0.

Proof of sin 2θ = 2 sin θ cos θ:

Using the sum formula: sin(θ + θ) = sin θ cos θ + cos θ sin θ

sin(θ + θ) = sin θ cos θ + sin θ cos θ = 2 sin θ cos θ

Therefore: sin 2θ = 2 sin θ cos θ

Example: If sin θ = 3/5 and θ is in Quadrant I, find sin 2θ.

Solution:

First find cos θ: cos²θ = 1 - (3/5)² = 1 - 9/25 = 16/25

cos θ = 4/5 (positive in Quadrant I)

sin 2θ = 2 sin θ cos θ = 2 × (3/5) × (4/5) = 24/25

Half Angle Formulas

These formulas express trigonometric functions of θ/2 in terms of functions of θ:

½

Sine Half Angle

sin(θ/2) = ±√[(1 - cos θ)/2]

Sign depends on quadrant of θ/2.

½

Cosine Half Angle

cos(θ/2) = ±√[(1 + cos θ)/2]

Sign depends on quadrant of θ/2.

½

Tangent Half Angle

tan(θ/2) = ±√[(1 - cos θ)/(1 + cos θ)]
= sin θ/(1 + cos θ)
= (1 - cos θ)/sin θ

Three equivalent forms with different applications.

Proof of sin(θ/2) = ±√[(1 - cos θ)/2]:

Start with the double angle formula for cosine: cos θ = 1 - 2 sin²(θ/2)

Rearrange: 2 sin²(θ/2) = 1 - cos θ

sin²(θ/2) = (1 - cos θ)/2

Take square root: sin(θ/2) = ±√[(1 - cos θ)/2]

Example: Find the exact value of sin(15°).

Solution:

sin(15°) = sin(30°/2) = √[(1 - cos30°)/2]

= √[(1 - √3/2)/2] = √[(2 - √3)/4] = √(2 - √3)/2

Product-to-Sum and Sum-to-Product Formulas

These formulas convert products of trigonometric functions into sums or differences, and vice versa:

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Product-to-Sum

sin A cos B = ½[sin(A+B) + sin(A-B)]
cos A sin B = ½[sin(A+B) - sin(A-B)]
cos A cos B = ½[cos(A+B) + cos(A-B)]
sin A sin B = ½[cos(A-B) - cos(A+B)]
➕➡️✖️

Sum-to-Product

sin X + sin Y = 2 sin[(X+Y)/2] cos[(X-Y)/2]
sin X - sin Y = 2 cos[(X+Y)/2] sin[(X-Y)/2]
cos X + cos Y = 2 cos[(X+Y)/2] cos[(X-Y)/2]
cos X - cos Y = -2 sin[(X+Y)/2] sin[(X-Y)/2]

Proof of sin A cos B = ½[sin(A+B) + sin(A-B)]:

Start with sum and difference formulas:

sin(A+B) = sin A cos B + cos A sin B

sin(A-B) = sin A cos B - cos A sin B

Add both equations: sin(A+B) + sin(A-B) = 2 sin A cos B

Divide by 2: sin A cos B = ½[sin(A+B) + sin(A-B)]

Example: Express sin 75° cos 15° as a sum.

Solution:

sin 75° cos 15° = ½[sin(75°+15°) + sin(75°-15°)]

= ½[sin 90° + sin 60°] = ½[1 + √3/2] = (2 + √3)/4

Challenge your problem-solving skills with applied exercises using the trigonometry calculator.

Practical Applications

Trigonometric identities have numerous real-world applications across various fields:

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Engineering

Signal Processing: Fourier analysis uses trigonometric identities to decompose signals into frequency components.

Structural Analysis: Calculating forces and stresses in trusses and bridges.

Electrical Engineering: AC circuit analysis using phasors and impedance calculations.

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Physics

Wave Mechanics: Modeling wave interference and superposition.

Orbital Mechanics: Calculating planetary orbits and satellite trajectories.

Quantum Mechanics: Solving Schrödinger's equation for various potentials.

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Computer Graphics

3D Transformations: Rotation matrices use trigonometric functions.

Animation: Creating smooth periodic motions and oscillations.

Game Development: Calculating trajectories, collisions, and lighting.

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Navigation

GPS Systems: Triangulation calculations using spherical trigonometry.

Aviation: Calculating headings, wind corrections, and great circle routes.

Surveying: Measuring distances and elevations indirectly.

Interactive Practice

Trigonometric Identity Verifier

Enter values to verify trigonometric identities and practice your skills.

Click "Verify Identities" to see identity verification for the entered angle.

Challenge: Prove that (1 - cos²θ)/(sin θ cos θ) = tan θ

Solution:

1. Start with left side: (1 - cos²θ)/(sin θ cos θ)

2. Use Pythagorean identity: 1 - cos²θ = sin²θ

3. Substitute: sin²θ/(sin θ cos θ) = sin θ/cos θ

4. Use quotient identity: sin θ/cos θ = tan θ

5. Therefore: (1 - cos²θ)/(sin θ cos θ) = tan θ

Challenge: Simplify sin(π/4 + x) + sin(π/4 - x)

Solution:

1. Use sum-to-product formula: sin A + sin B = 2 sin[(A+B)/2] cos[(A-B)/2]

2. Here A = π/4 + x, B = π/4 - x

3. (A+B)/2 = [(π/4+x)+(π/4-x)]/2 = (π/2)/2 = π/4

4. (A-B)/2 = [(π/4+x)-(π/4-x)]/2 = (2x)/2 = x

5. Therefore: sin(π/4+x) + sin(π/4-x) = 2 sin(π/4) cos x = 2(√2/2) cos x = √2 cos x

Trigonometric Identities Cheat Sheet

Category Identity Formula
Reciprocal Cosecant csc θ = 1/sin θ
Reciprocal Secant sec θ = 1/cos θ
Reciprocal Cotangent cot θ = 1/tan θ
Quotient Tangent tan θ = sin θ/cos θ
Quotient Cotangent cot θ = cos θ/sin θ
Pythagorean Fundamental sin²θ + cos²θ = 1
Pythagorean Tangent-Secant 1 + tan²θ = sec²θ
Pythagorean Cotangent-Cosecant 1 + cot²θ = csc²θ
Sum/Difference Sine sin(A±B) = sin A cos B ± cos A sin B
Sum/Difference Cosine cos(A±B) = cos A cos B ∓ sin A sin B
Double Angle Sine sin 2θ = 2 sin θ cos θ
Double Angle Cosine cos 2θ = cos²θ - sin²θ = 2 cos²θ - 1 = 1 - 2 sin²θ
Half Angle Sine sin(θ/2) = ±√[(1 - cos θ)/2]
Half Angle Cosine cos(θ/2) = ±√[(1 + cos θ)/2]
Memory Tips
  • SOH-CAH-TOA: Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse, Tangent = Opposite/Adjacent
  • All Students Take Calculus: Quadrants where trig functions are positive (All, Sine, Tangent, Cosine)
  • Pythagorean Triples: 3-4-5, 5-12-13, 8-15-17 help remember common trigonometric values
  • Sum Formulas: "Sine keeps the sign, cosine changes it" for sin(A±B) and cos(A±B)

Confirm your learning by applying it in realistic scenarios using the trigonometry calculator.